Vertex Axis Of Symmetry Of A Parabola Video Khan Academy
Axis of symmetry is found by converting to vertex form y = x^2−4x−12 y = (x 2)^2 4 12 y = (x 2)^2 16 So axis of symmetry is x = 2 Vertex is at (2, 16) Domain is all Real Numbers Range is y ≥ 16 Advertisement Advertisement New questions in MathematicsThe xintercept is where the graph crosses the xaxis It is also known as the value/s of x when y = 0, hence 0=2x2−4x3 To check the nature of its roots, we find the discriminant d=b2−4ac d=(−4)2−4(2)(3) d=−8 Since the discriminant is negative,